(y^2)=(3/2)(y+1)

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Solution for (y^2)=(3/2)(y+1) equation: 



(y^2)=(3/2)(y+1)

We move all terms to the left:

(y^2)-((3/2)(y+1))=0



Domain of the equation: 2)(y+1))!=0

y∈R



We add all the numbers together, and all the variables

y^2-((+3/2)(y+1))=0

We multiply parentheses ..

y^2-((+3y^2+3/2*1))=0

We multiply all the terms by the denominator


3y^2+y^2*2*1))-((+3=0

Wy multiply elements

3y^2+2y^3*1+3=0

We do not support eypression: y^3

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